jika diketahui lim x mendekati -2. x²-4 / x+2= lim mendekati x mendekati 1 ax²+b dan lim x mendekati 2 ax²+b=2 maka nilai a-b=
Jawab:
a-b = 8
Penjelasan dengan langkah-langkah:
[tex]\displaystyle \lim_{x\to -2} \frac{x^2-4}{x+2} = \lim_{x\to 1}ax^2+b\\\lim_{x\to -2} x-2 = \lim_{x\to 1}ax^2+b\\\\-4 =a+b \to b = -(a+4)\\\\\lim_{x\to 2} ax^2+b=2\to 4a+b = 2\\\\ 4a-(a+4) = 2\to a = 2, b = -6\\\\\Huge{\boxed{\boxed{\boldsymbol{a-b = 8}}}[/tex]
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